x^2-10=2x^2+1

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Solution for x^2-10=2x^2+1 equation: 



x^2-10=2x^2+1

We move all terms to the left:

x^2-10-(2x^2+1)=0

We get rid of parentheses

x^2-2x^2-1-10=0

We add all the numbers together, and all the variables

-1x^2-11=0

a = -1; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·(-1)·(-11)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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